A050259 and a new solution to 2^n = 3 (mod n)

[Jonathan Post]

Is this a hierarchy of fame, or a graph, or directed graph, or a lattice, or
what? What percentage of "nice" sequences are referenced in each successive
edition of UPINT (Unsolved problems in Number Theory)? How many OEIS seqs
per edition of UPINT, now that the two are more tightly interlinked? What
estimates does one make to extrapolate for future editions? Should there be
a "very nice" keyword for seqs that pose problems in UPINT, when they get
solved in later editions?

Only hypothetical for me, as I've had over 1400 seqs in OEIS and not one is
yet "nice", although some are comments on "nice" seqs. So if there is a
hierarchy of fame, I'm just above the lowest  level (or highest, depending
on indexing) in quality, which is most assuredly not correlated well with
quantity.  In Science Fiction, for instance, there are indeed a hierarchies
of fame, based on awards (Hugo, Nebula), coauthorships, pay, anthologies,
and the like.  I'm also just somewhat above the bottom, in part for my
coauthorships with Asimov, Bradbury, Clarke, and Heinlein.  I've done
research on Asimov Number as the Science Fiction equivalent of Erdos Number,
but that's another story.

By the way, I have the penultimate edition (so far) of UPINT as a gift from
the wonderful Tony Noe, when he bought the ultimate edition (so far). I echo
the applause by njas for all the hundreds of errors in OEIS found and
corrected by Tony, and the many many b-files.

Best,

Jonathan Vos Post

On 11/13/06, Richard Guy <rkg at cpsc.ucalgary.ca> wrote:
>
> Congratulations!  May I know Max's full name,
> so that he can earn undying fame in UPINT as
> well as in OEIS ?   Thanks,   R.
>
> On Mon, 13 Nov 2006, Max A. wrote:
>
> > SeqFans,
> >
> > In course of exploring all solutions of the congruence 2^n = 3
> > (mod n)
> > below 10^16, I have found a new solution:
> >
> > n = 3468371109448915
> >
> > This came as a big surprise to me since my original goal was
> > to prove
> > that 8365386194032363 is the second term of A050259. But now
> > it
> > appears to be at least the third term.
> >
> > So far I've submitted the new solution as a comment to
> > A050259, but
> > hopefully it will take its true place in this sequence soon.
> >
> > Regards,
> > Max
> >
> > P.S. See also http://mathworld.wolfram.com/2.html
>
>
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