%F A135057 A135057(n)=100^n/4-(A124049(n))^2

[zak seidov]

%F A135057 A135057(n)=100^n/4-(A124049(n))^2 - Zak
Seidov (zakseidov(AT)yahoo.com), Feb 15 2008.
%Y A135057 A124049


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