[seqfan] Re: 2^k - prime(p) or prime(p) - 2^k ?

israel at math.ubc.ca israel at math.ubc.ca
Wed Apr 10 20:33:06 CEST 2013


It seems to me that the criterion is that p + ithprime(p) is a power of 2.
Thus 503 is prime, the 503'th prime is 3593, and 503 + 3593 = 2^12.
No others past 503 in the first 10000 primes.

Robert Israel
University of British Columbia

On Apr 10 2013, Charles Greathouse wrote:

>> Hello, SegFans, Primes p of the form 2^k - prime(p) for some k:  3, 5,
>503,...?
>
>How would you prove the absence of a term? And what about 11 = 16 - 5, 13 =
>16 - 3, 19 = 128 - 109, 23 = 64 - 41, 29 = 32 - 3, and so forth?
>
>Charles Greathouse
>Analyst/Programmer
>Case Western Reserve University
>
>
>On Tue, Apr 9, 2013 at 5:21 AM, юрий герасимов <2stepan at rambler.ru> wrote:
>
>>
>> Hello, SegFans, Primes p of the form 2^k - prime(p) for some k:  3, 5,
>> 503,...? or Primes p of the form prime(p) - 2^k for some  k:  2, 3,...?
>> Best regards, JSG.
>>
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