[seqfan] Re: Fibonaccit

Hans Havermann gladhobo at teksavvy.com
Sat Feb 16 17:53:44 CET 2013

Lars Blomberg:

> I have found no loop within the first 10^8 terms.

Hey Lars. :)

As a non-mathematician I can't quite formalize a proof, but consider those consecutive 18s mentioned in my previous post. A stretch of k 18s will generate roughly 2k 9s in the corresponding summed-digits list, which in turn generate 2k 18s. Thus the number of consecutive 18s will grow without limit and no loops are possible.

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