[seqfan] Re: Sharing no digit business

Hans Havermann pxp at rogers.com
Fri Apr 3 16:48:39 CEST 2009

Eric Angelini:

> "a(n) shares no digit with the a(n)th term of the sequence"

This confuses me (although others seem to have understood it). Do you  
mean that a(n) shares no digits with the digits of n? If so, does  
a(123456789) exist?

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