[seqfan] Re: More terms for A225053: Second terms of continued fractions for power towers e, e^e, e^e^e, ...
Charles Greathouse
charles.greathouse at case.edu
Fri May 3 16:29:40 CEST 2013
What you need for this problem are the first few decimal places of
e^e^e^e^e after the decimal point. I don't know of any way to get that.
Hypercalc certainly won't find them.
Charles Greathouse
Analyst/Programmer
Case Western Reserve University
On Fri, May 3, 2013 at 9:48 AM, Georgi Guninski <guninski at guninski.com>wrote:
> On Mon, Apr 29, 2013 at 03:52:09PM -0700, Vladimir Reshetnikov wrote:
> > Dear SeqFans,
> >
> > I am looking for ideas how to calculate more terms for
> > A225053<http://oeis.org/A225053>
> > .
> > Particularly, is it feasible to determine at least a(5) =
> > floor(1/frac(e^e^e^e^e))?
> >
>
> In mrob's hypercalc:
>
> C2 = e^e^e^e^e;
> R2 = 10 ^ ( 1.01255953 x 10 ^ 1656520 )
>
>
> > And it would be a delightful surprise if e^e^e^e^e turned out to be an
> > integer :-)
> >
> > --
> > Thanks
> > Vladimir Reshetnikov
> >
> > _______________________________________________
> >
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>
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