[seqfan] Re: a(n+1) is the multiple of at least one digit of a(n)
Eric.Angelini at kntv.be
Tue May 28 23:42:36 CEST 2013
Agree, Hans, well thought !
Propulsé d'un aPhone
Le 28 mai 2013 à 21:04, "Hans Havermann" <gladhobo at teksavvy.com> a écrit :
> Conjecture: For nonnegative integer n, 2*10^n appears at index 2*10^n.
> On May 28, 2013, at 10:46 AM, Eric Angelini <Eric.Angelini at kntv.be> wrote:
>> I guess this is a permutation of the Naturals:
>> a(n+1) is the smallest integer not yet in the sequence such that
>> a(n+1) is the multiple of at least one digit of a(n):
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