[seqfan] Re: Surprising Patterns in Tangent and Secant Numbers
Paul D Hanna
pauldhanna at juno.com
Tue Nov 10 14:09:20 CET 2009
Franklin (and SeqFans),
I appreciate your consideration, but perhaps you dismiss the situation too quickly.
The surprise is not that the e.g.f. exp(x)/cosh(x) = 1 + tanh(x)
has zeros every other term, but that the alternating zeros
also occur under the transformation of the o.g.f.:
F(x) = 1 + x - 2*x^3 + 16*x^5 - 272*x^7 + 7936*x^9 +...
> Now if we define B(x) by:
> B(x) = F(x/B(x)) and F(x) = B(x*F(x))
> so that
> B(x) = x/Series_Reversion(x*F(x))
> = 1 + x - x^2 + 3*x^4 - 38*x^6 + 947*x^8 - 37394*x^10 +...
> then we observe that B(x) is a function that also has
> alternating zero coefficients, but at odd positions (>1):
> A157308 = [1,1,-1,0,3,0,-38,0,947,0,-37394,0,2120190,0,...].
The re-emergence of alternating zeros occurring at opposite positions is not trivial;
it is unique under that transformation (given that the function begins 1+x+...).
x/Series_Reversion[x/(1+x^2) +x^2] = 1 + x - 2*x^2 + 5*x^3 - 16*x^4 + 59*x^5 - 233*x^6 +...
In this example, the resultant series is neither odd nor even under the transformation,
even though we started with x/(1+x^2) +x^2 = x + x^2 - x^3 + x^5 - x^7 + x^9 +...
which clearly has alternating zero coefficients after the initial terms.
I believe that the behavior is directly linked to the following identity:
= x + x/serreverse(x*serlaplace(1/cosh(x)))
= 1 + x - x^2 + 3*x^4 - 38*x^6 + 947*x^8 - 37394*x^10 +...
Prove this identity and the other observations (I think) should follow by logical deduction.
---------- Original Message ----------
From: franktaw at netscape.net
To: seqfan at list.seqfan.eu
Subject: [seqfan] Re: Surprising Patterns in Tangent and Secant Numbers
Date: Tue, 10 Nov 2009 04:51:14 -0500
You're making this harder than it really is. A function has zeros in
odd positions iff it is an even function (that is, f(-x) = -f(x)), and
zeros in even positions if it is an odd function (f(-x) = f(x)). So
the tangent numbers have zeros in even positions except the constant
exp(x)/cosh(x) - 1 = (exp(x) - exp(-x))/(exp(x) + exp(-x))
is odd; and by inspection, it is.
I'm less clear about what is happening in A157310, but I would
definitely approach it by trying to show that C(x) - 1 is an odd
Franklin T. Adams-Watters
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