[seqfan] Re: LRS formulas for n>=...?
Hagen von Eitzen
math at von-eitzen.de
Mon Aug 3 22:23:53 CEST 2009
rhhardin at att.net schrieb:
> Yes, that looks good.
>
> In fact just proving the existence of a recursion is enough to prove
> an empirical recursion, with some decision about how many terms
> it might have at most.
>
> Enumeration of enough terms fades fast as m increases in nXm however.
>
>
BTW, I'm missing sequences without any "path form here to there"
condition, i.e.
let F(n,m) be the number of nxm binary arrays with all 1's connected and
no 1 having more than two 1s adjacent.
Then e.g. your A000032(n) = F(n,4) - 2*F(n-1,4) + F(n-2,4) and
A000040(n) = F(n,4) - 2*F(n,3) + F(n,2).
Hagen
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