[seqfan] Re: a partition sequence
David Newman
davidsnewman at gmail.com
Mon Oct 3 00:13:27 CEST 2011
You are right. 3 3 is a typo. It should have been
3
3
On Sun, Oct 2, 2011 at 6:09 PM, William Keith <william.keith at gmail.com>wrote:
> On Sun, Oct 2, 2011 at 10:22 PM, David Newman <davidsnewman at gmail.com
> >wrote:
>
> > I'd like someone to check my numbers before I propose this sequence.
> >
> > Let a(n) be the number of planar partitions whose summands are
> > distinct going across rows and have distinct frequencies going down
> > columns.
> >
>
> You'd better be more precise. I understand this as near as I can to mean
> that each row consists of distinct summands, and the list of frequencies of
> summands in each column (other than an infinite set of 0s) is a list of
> distinct numbers for each summand. However:
>
> 3 3
> >
>
> There are two 3s in this partition, and the list of frequencies of 3s in
> each column is 1 and 1.
>
> So either there's something off with your calculations or I didn't
> understand your definition.
>
> William Keith
>
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