[seqfan] Simple seq with 3 in 4
Eric.Angelini at kntv.be
Sat Aug 21 18:30:19 CEST 2010
I must have missed the correct entry
in the OEIS because I cannot find this
easy (core?) seq.
"To find 3 consecutive naturals in S,
you have to take 4 consecutive terms
of S -- no less":
Ex: taking the first 3 terms doesn't
allow you to handle 3 consecutive
natural numbers as they are 0,1 and... 3.
But if you take the fourth term (2),
you'll have in hand 0,1,2 [and even
another triplet of consecutive naturals,
which is (1,2,3)].
Formula is easy to compute.
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